The displacement is given by ` x = 2t^(2) + t + 5` , the acceleration at t = 5 sec will be-

Options

A. ` 8 m//s^(2)`
B. `12 m//s^(2)`
C. `15 m//s^(2)`
D. `4 m//s^(2)`

Explanation

To find the acceleration at \( t = 5 \) seconds given the displacement function \( x(t) = 2t^2 + t + 5 \), we will follow these steps:

### Step 1: Differentiate the displacement function to find the velocity.
The displacement is given by:
\[ x(t) = 2t^2 + t + 5 \]
To find the velocity \( v(t) \), we differentiate \( x(t) \) with respect to \( t \):
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