Home
Class 12
PHYSICS
The position x of a particle varies with...

The position `x` of a particle varies with time `t` as `x=at^(2)-bt^(3)`. The acceleration at time `t` of the particle will be equal to zero, where (t) is equal to .`

A

`(2a)/(3b)`

B

`(a)/(b)`

C

`(a)/(3b)`

D

0

Text Solution

Verified by Experts

Given that ` x = at^(2) – bt^(3)`
` therefore ` Velocity ` v = (dx)/(dt) = 2at - 3bt^(2) ` and
acceleration ` a = (d)/(dt) ((dx)/(dt)) rArr = 0 2a - 6bt `
` rArr t = (2a)/(6b) = (a)/(3b) `
Hence correct answer is (C)
Promotional Banner

Topper's Solved these Questions

  • ONE DIMENSION MOTION

    MOTION|Exercise EXERCSE -1 (Section - A : Distance, Displacement, Velocity and Acceleration, Equation of Motion )|26 Videos

  • ONE DIMENSION MOTION

    MOTION|Exercise EXERCSE -1 (Section - B : Motion under Gravity)|11 Videos

  • NLM & FRICTION

    MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos

  • OPTICS

    MOTION|Exercise Exercise|45 Videos

Similar Questions

Explore conceptually related problems

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

The position x of a particle varies with time t as X=at^(2)-bt^(3).The acceleration of the particle will be zero at time (t) equal to

The position x of a particle varies with time t as x=a t^(2)-b . For what value of t acceleration is zero?

The position x of a body is defined by equation x = Pt^(2)- Q t^(3) . The acceleration of the particle will be zero at time equal to

The position of a point in time t is given by x=a+bt-ct^(2),y=at+bt^(2) . Its acceleration at time t is

The position of a point in time t is given by x=a+bt-ct^(2),y=at+bt^(2) . Its acceleration at time t is

The distance covered by a particle varies with as x=k/b(1-e^(-bt)) . The speed of particle at time t is