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A car acceleration form rest at a consta...

A car acceleration form rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta`, to come to rest. If the total time elapsed is t evaluate (a) the maximum velocity attained and (b) the total distance travelled.

A

`(alpha beta)/((alpha + beta)t)`

B

`(alpha^(2) beta)/((alpha + beta)) t `

C

`(alpha beta)/((alpha beta)) t `

D

`(alpha beta^(2) t)/((alpha beta))`

Text Solution

Verified by Experts

From “ v = u + at” we have, for the car,
`v = 0 + alpha t_(1) "and " 0 = v – beta t_(2)`
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