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A car accelerates from rest at a constan...

A car accelerates from rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta,` to come to rest. If the total time elapsed is t seconds. Then evalute (a) the maximum velocity reached and (b) the total distance travelled.

A

` v = t (alpha beta)/(alpha - beta)`

B

`v = t ((beta^(2))/(alpha - beta))`

C

`v = t ((a^(2))/(alpha + beta))`

D

`v = t ((alpha beta)/(alpha + beta))`

Text Solution

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The correct Answer is:
D
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MOTION-ONE DIMENSION MOTION-EXERCSE -1 (Section - A : Distance, Displacement, Velocity and Acceleration, Equation of Motion )
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  10. A body starting from rest and has uniform acceleration 8 m//s^(2) . ...

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