A body is moving from rest under constan...

A body is moving from rest under constant acceleration and let `S_1` be the displacement in the first `(p - 1)` sec and `S_2` be the displacement in the first `p` sec. The displacement in `(p^2 - p + 1)` sec. will be

`S_(1) + S_(2)`

`S_(1) S_(2)`

`S_(1) - S_(2)`

`(S_(1))/(S_(2))`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

ONE DIMENSION MOTION
MOTION|Exercise EXERCSE -1 (Section - B : Motion under Gravity)|11 Videos
ONE DIMENSION MOTION
MOTION|Exercise EXERCSE -1 (Section - C : Relative Motion)|9 Videos
ONE DIMENSION MOTION
MOTION|Exercise Exercise - 3 |Section - B Previous Year Problems | JEE MAIN|12 Videos
NLM & FRICTION
MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos
OPTICS
MOTION|Exercise Exercise|45 Videos

Similar Questions

Explore conceptually related problems

A body is moving from rest under constance accelration and let S_1 be the displacement in the first (p-1) sec and S_2 be the displacement in the first p sec. The displacement in (p^2-p+1)^(th) sec will be

A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A particle starts moving from rest under uniform acceleration.It travels a distance x in the first 2 sec and a distance in the next 2sec.If u=nx then n is

A body moves from rest with a constant acceleration of 5m//s^(2) . Its instantaneous speed (in m/s) at the end of 10 sec is

A particle starts moving from the position of rest under a constant acc. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then:

A particle is moving under constant acceleration a=k t . The motion starts from rest. The velocity and displacement as a function of time t is

A body starting from rest moving with uniform acceleration has a displacement of 16 m in first 4 seconds and 9 m in first 3 seconds. The acceleration of the body is :

MOTION-ONE DIMENSION MOTION-EXERCSE -1 (Section - A : Distance, Displacement, Velocity and Acceleration, Equation of Motion )

The position of a body with respect to time is given by x = 4t^(3) – 6...
Text Solution
|
A car travels along a straight line for first half time with speed 40 ...
Text Solution
|
A truck travelling due north at 20 m/s turns east and travels at the s...
Text Solution
|
A motor car covers 1//3^(rd) part of total distance with v(1) = 10 ...
Text Solution
|
A particle travels A to M along a straight line with a velocity of 8 m...
Text Solution
|
At an instasnt t the coordinates of a particles are x=at^(2), y=bt^(2)...
Text Solution
|
The displacement time graph of a moving particle is shown below T...
Text Solution
|
Figure shows four paths along which objects move from a starting poi...
Text Solution
|
Figure shows the path followed by a particle. Its velocity is shown at...
Text Solution
|
A body starting from rest and has uniform acceleration 8 m//s^(2) . ...
Text Solution
|
A car accelerates from rest at a constant rate alpha for some time, af...
Text Solution
|
The distance x travelled by the car in above problem in time t is give...
Text Solution
|
A train, travelling at 20 km//hr is approaching a platform. A bird is ...
Text Solution
|
A body moves with uniform velocity of u = 7 m/s from t = 0 to t = 1.5 ...
Text Solution
|
A driver applies the brakes on seeing traffic signal 400m ahead. At th...
Text Solution
|
The position of a particle is expressed as vecr = ( 4t^(2) hati + 2th...
Text Solution
|
The position of a particel is expressed as vecr = ( 4t^(2)hati + 2tha...
Text Solution
|
A thief is running away on a straight road in a jeep moving with a spe...
Text Solution
|
A disc arranged in a vertical plane has two groves of same length dire...
Text Solution
|
A body is moving from rest under constant acceleration and let S1 be t...
Text Solution
|