The time period of of alternating current with frequency of one KHz one second will be –

Options

A. 0.1
B. 0.01
C. `1xx10^(-3)`
D. `1xx10^(-2)`

Answer

To find the time period of an alternating current with a frequency of 1 kHz, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between frequency and time period**:
The time period (T) of an alternating current is the reciprocal of the frequency (f). This relationship is given by the formula:
\[ T = \frac{1}{f} \]

2. **Convert the frequency from kHz to Hz**:
The frequency is given as 1 kHz. We need to convert this to Hertz (Hz):
\[ 1 \text{ kHz} = 1000 \text{ Hz} = 1 \times 10^3 \text{ Hz} \]

3. **Substitute the frequency into the formula**:
Now, we can substitute the frequency into the formula for the time period:
\[ T = \frac{1}{1 \times 10^3} \]

4. **Calculate the time period**:
Performing the calculation gives:
\[ T = \frac{1}{1000} = 0.001 \text{ seconds} \]

5. **Express the time period in scientific notation**:
The time period can also be expressed in scientific notation:
\[ T = 1 \times 10^{-3} \text{ seconds} \]

### Final Answer:
The time period of the alternating current with a frequency of 1 kHz is:
\[ T = 1 \times 10^{-3} \text{ seconds} \]