In the equation for A.C. `I =I _(0) sin omegat`, the current amplitude and frequency will respectively be

Options

A. `I_(0), (omega)/(2pi)`
B. `(I_(0))/(2) , (omega)/(2pi)`
C. `I_("rms"), (omega)/(2pi)`
D. `I_(0),omega`

Answer

To solve the question regarding the equation for alternating current \( I = I_0 \sin(\omega t) \), we need to identify the current amplitude and frequency from the given equation.

### Step-by-Step Solution:

1. **Identify the Equation**: The equation for alternating current is given as:
\[ I = I_0 \sin(\omega t) \]
Here, \( I \) is the instantaneous current, \( I_0 \) is the current amplitude, \( \omega \) is the angular frequency, and \( t \) is time.

2. **Determine the Current Amplitude**: In the equation, \( I_0 \) represents the maximum value of the current, also known as the peak current or current amplitude. Therefore, the current amplitude is:
\[ \text{Current Amplitude} = I_0 \]

3. **Determine the Frequency**: The angular frequency \( \omega \) is related to the frequency \( f \) by the formula:
\[ \omega = 2\pi f \]
To find the frequency \( f \), we rearrange this equation:
\[ f = \frac{\omega}{2\pi} \]

4. **Final Answers**:
- The current amplitude is \( I_0 \).
- The frequency is \( \frac{\omega}{2\pi} \).

### Summary:
- Current Amplitude: \( I_0 \)
- Frequency: \( \frac{\omega}{2\pi} \)