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Alternating current lead the applied e.m...

Alternating current lead the applied e.m.f. by `pi`/2 when the circuit consists of –

A

only resistance

B

only capacitor

C

only an inductance coil

D

capacitor and resistance both

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The correct Answer is:
To solve the question, "Alternating current leads the applied e.m.f. by π/2 when the circuit consists of –", we need to analyze the behavior of alternating current (AC) in different types of circuits. ### Step-by-Step Solution: 1. **Understanding Phase Difference**: - In AC circuits, the phase difference between the current (I) and the voltage (V) is crucial. If the current leads the voltage by π/2, it indicates a specific relationship between them. 2. **Identifying Circuit Types**: - There are two main types of reactive components in AC circuits: capacitors and inductors. - In a purely inductive circuit, the current lags behind the voltage by π/2. - In a purely capacitive circuit, the current leads the voltage by π/2. 3. **Analyzing the Given Condition**: - The question states that the alternating current leads the applied e.m.f. by π/2. This means that the current reaches its maximum value before the voltage does. 4. **Conclusion**: - Since the current leads the voltage by π/2, it indicates that the circuit must be purely capacitive. In a purely capacitive circuit, the voltage lags the current by π/2, which is the condition described in the question. 5. **Final Answer**: - Therefore, the answer to the question is that the circuit consists of a **purely capacitive circuit**.
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