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In an LCR. series circuit the resonating...

In an LCR. series circuit the resonating frequency can be decreased by -

A

Decreasing the value of C

B

Decreasing the value of L

C

Decreasing both the values of L and C

D

Increasing the value of C

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The correct Answer is:
To solve the question regarding how to decrease the resonating frequency in an LCR series circuit, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Resonating Frequency Formula:** The resonating frequency \( f \) in an LCR series circuit is given by the formula: \[ f = \frac{1}{2\pi\sqrt{LC}} \] where \( L \) is the inductance and \( C \) is the capacitance. 2. **Analyze the Relationship:** From the formula, we can see that the resonating frequency \( f \) is inversely proportional to the square root of the product of \( L \) and \( C \). This means: \[ f \propto \frac{1}{\sqrt{LC}} \] 3. **Determine How to Decrease Frequency:** To decrease the resonating frequency \( f \), we need to increase the value of either \( L \) (inductance) or \( C \) (capacitance) or both. This is because increasing \( L \) or \( C \) will increase the denominator in the formula, thereby decreasing the frequency. 4. **Conclusion:** Therefore, the resonating frequency can be decreased by increasing the values of \( L \) and/or \( C \). ### Final Answer: The resonating frequency in an LCR series circuit can be decreased by **increasing the values of inductance \( L \) and/or capacitance \( C \)**. ---
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