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A circuit contains R, L and C connected ...

A circuit contains R, L and C connected in series with an A. C. source. The values of the reactances for inductor and capacitor are `200Omega` and `600Omega` respectively and the impedance of the circuit is Z1 . What happens to the impedance of the same circuit if the values of the reactances are interchanged:-

A

The impedance will remain unchanged

B

The impedance will increase

C

The impedance will decrease

D

The phase angle will remain unchanged

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the impedance of a series RLC circuit with given reactances for the inductor and capacitor. We will also consider what happens when the reactances are interchanged. ### Step-by-step Solution: 1. **Identify the given values:** - Reactance of the inductor \( X_L = 200 \, \Omega \) - Reactance of the capacitor \( X_C = 600 \, \Omega \) 2. **Calculate the net reactance for the initial configuration:** - In a series RLC circuit, the total reactance \( X \) is given by: \[ X = X_L - X_C \] - Substituting the values: \[ X = 200 \, \Omega - 600 \, \Omega = -400 \, \Omega \] - The negative sign indicates that the circuit is capacitive. 3. **Calculate the impedance \( Z_1 \) for the initial configuration:** - The impedance \( Z \) in a series circuit is given by: \[ Z = \sqrt{R^2 + X^2} \] - Substituting for \( X \): \[ Z_1 = \sqrt{R^2 + (-400)^2} = \sqrt{R^2 + 160000} \] 4. **Interchange the reactances:** - Now, let’s interchange the reactances: - New reactance of the inductor \( X_L' = 600 \, \Omega \) - New reactance of the capacitor \( X_C' = 200 \, \Omega \) 5. **Calculate the net reactance for the new configuration:** - Again, using the formula for total reactance: \[ X' = X_L' - X_C' = 600 \, \Omega - 200 \, \Omega = 400 \, \Omega \] - The positive sign indicates that the circuit is inductive. 6. **Calculate the impedance \( Z_2 \) for the new configuration:** - The impedance for the new configuration is: \[ Z_2 = \sqrt{R^2 + (400)^2} = \sqrt{R^2 + 160000} \] 7. **Compare the two impedances:** - We find that: \[ Z_1 = \sqrt{R^2 + 160000} \] \[ Z_2 = \sqrt{R^2 + 160000} \] - Therefore, \( Z_1 = Z_2 \). ### Conclusion: The impedance of the circuit remains unchanged when the values of the reactances are interchanged.
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