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A source of 220V is applied in an A.C. c...

A source of 220V is applied in an A.C. circuit. The value of resistance is `220Omega`. Frequency & inductance are 50 Hz and 0.7 H, then wattless current is

A

0.5 amp

B

0.7 amp

C

1.0 amp

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To find the wattless current in the given AC circuit, we can follow these steps: ### Step 1: Identify the given values - Voltage (V) = 220 V - Resistance (R) = 220 Ω - Frequency (f) = 50 Hz - Inductance (L) = 0.7 H ### Step 2: Calculate the maximum current (I₀) The maximum current (I₀) can be calculated using Ohm's law: \[ I₀ = \frac{V}{R} \] Substituting the values: \[ I₀ = \frac{220 \, \text{V}}{220 \, \Omega} = 1 \, \text{A} \] ### Step 3: Calculate the RMS current (Iₘₛ) The RMS current (Iₘₛ) is given by: \[ Iₘₛ = \frac{I₀}{\sqrt{2}} \] Substituting the value of I₀: \[ Iₘₛ = \frac{1 \, \text{A}}{\sqrt{2}} \approx 0.707 \, \text{A} \] ### Step 4: Calculate the inductive reactance (Xₗ) The inductive reactance (Xₗ) can be calculated using the formula: \[ Xₗ = 2 \pi f L \] Substituting the values: \[ Xₗ = 2 \pi (50 \, \text{Hz}) (0.7 \, \text{H}) \] \[ Xₗ \approx 2 \times 3.14 \times 50 \times 0.7 \approx 220 \, \Omega \] ### Step 5: Calculate the phase angle (φ) The phase angle (φ) can be calculated using: \[ \tan φ = \frac{Xₗ}{R} \] Substituting the values: \[ \tan φ = \frac{220 \, \Omega}{220 \, \Omega} = 1 \] Thus, \[ φ = 45^\circ \] ### Step 6: Calculate the wattless current (Iₗ) The wattless current (Iₗ) can be calculated using: \[ Iₗ = Iₘₛ \sin φ \] Since \( \sin 45^\circ = \frac{1}{\sqrt{2}} \): \[ Iₗ = 0.707 \, \text{A} \times \frac{1}{\sqrt{2}} \] \[ Iₗ = \frac{0.707}{\sqrt{2}} = 0.5 \, \text{A} \] ### Final Answer: The wattless current is \( 0.5 \, \text{A} \). ---
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