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" 14."cot(xy)+xy=y...

" 14."cot(xy)+xy=y

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Find (dy)/(dx) , when: cot(xy)+xy=y

Find dy/dx when cot (y) + xy = y

Find the derivative of cot( x+ y ) = xy with respect to x .

If xy = tan^(-1) (xy) + cot^(-1) (xy), " then" (dy)/(dx) is equal to

(sin x + sin y) / (sin x-sin y) = tan ((x + y) / (2)) * cot ((xy) / (2))

cos x + cos y = (4) / (5), cos x-cos y = (2) / (7) rArr14tan ((xy) / (2)) + 5cot ((x + y) / (2)) =

cos x + cos y = (4) / (5), cos x-cos y = (2) / (7) rArr14tan ((xy) / (2)) + cot ((x + y) / (2)) =

Prove that : tan^(-1) x+cot^(-1) y = tan^(-1) ((xy+1)/(y-x))

Prove that : tan^(-1) x+cot^(-1) y = tan^(-1) ((xy+1)/(y-x))