Find the equation of the curve passing through origin if the slope of the tangent to the curve at any point `(x ,y)i s` equal to the square of the difference of the abscissa and ordinate of the point.

Explanation

Given,
difference of abscissa and ordinate `=x−y`

And,

`(dy)/(dx)​=(x−y)^2 ->(i)`

let,

` x−y=z`

`=>(dy)/(dx)​=(dx)/(dx)​`

`=>(dy)/(dx)​=1−(dz)/(dx)​`

Putting in `Eq (i)`, we get

...