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One end of a copper rod of length 1.0 m ...

One end of a copper rod of length 1.0 m and area of cross-section `10^(-3)` is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is `92 cal//m-s-.^(@)C` and the latent heat of ice is `8xx 10^(4) cal//kg`, then the amount of ice which will melt in one minute is

Text Solution

Verified by Experts

Rate of heat conduction through rod is
`(dQ)/(dt)=(kA)/(l)(100)=(92xx10xx10^(-4))/(1)xx100`
`9.2cal//s`
if m gm ice melt per second we use
`(dQ)/(dt)=mL`
`9.2=mxx80`
`m=(9.2)/(80)g//s`
mass melt in one minute is
`m'(9.2)/(80)xx60=6.9g`
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