When `(0,0)` shifted to `(2,-2)` the transformed equation of `(x-2)^(2)+(y+2)^(2)=9` is

When (0,0) is shifted to (2,-2) ,if the transformed equation of (x-2)^(2)+(y+2)^(2)=9 is X^(2)+Y^(2)=k , then k^(2) is equal to

When (0,0) is shifted to (2,-2) ,if the transformed equation of (x-2)^(2)+(y+2)^(2)=9 is X^(2)+Y^(2)=k ,then k+11 is equal to

Keeping coordinate axes parallel, the origin is shifted to a point (1, –2), then transformed equation of x^2 + y^2 = 2 is -

If origin is shifted to (-2,3) then transformed equation of curve x^(2)+2y-3=0 w.r.t.to (0,0) is

If origin is shifted to (-2,3) then transformed equation of curve x^(2)+2y-3=0 w.r.t.to (0, 0) is

When the origin is shifted to (2,3) then the original equation of x^(2)+y^(2)+4x+6y+12=0 is

Find the point at which origin is shifted such that the transformed equation of x^(2)+2y^(2)-4x+4y-2=0 has no first degree term. Also find the transformed equation .

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

The equation (x+y)^(2)-(x^(2)+y^(2))=0 represents