" The radical centre of the circles "x^(2)+y^(2)-x+3y-3=0,x^(2)+y^(2)-2x+2y-2=0,x^(2)+y^(2)+2x+3y-

The radical center of the circles x^(2)+y^(2)-4x-6y+5=0 , x^(2)+y^(2)-2x-4y-1=0 , x^(2)+y^(2)-6x-2y=0 .

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

if the radical centre of the three circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)-3y=1 and 2x^(2)+2y^(2)-x-7y-2=0 is Q then Q_(x)+Q_(y) is

The radical centre of x^(2)+y^(2)-2x-2y+1=0, x^(2)+y^(2)-4x+6y-2=0 and x^(2)+y^(2)+3x-2y+4=0 is

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameters of a circle of circumference 10 pi ,then the equation of the circle is (A) x^(2)+y^(2)-2x+2y-23=0 (B) x^(2)+y^(2)+2x-2y-23=0 (C) x^(2)+y^(2)+2x+2y-23=0 (D) x^(2)+y^(2)-2x-2y-23=0