The tangent of the circle `x^(2)+y^(2)-2x-4y-20=0` at `(1,7)` meets the y -axis at the point

find the equation of the tangents to the circle x^(2)+y^(2)-2x-4y-20=0 which pass through the point (8,1)

The tangents to the circle x^(2)+y^(2)-4x+2y+k=0 at (1,1) is x-2y+1=0 then k=

Let A be the centre of the circle x^(2)+y^(2)-2x-4y-20=0 . If the tangents at the points B (1, 7) and D(4, -2) on the circle meet at the point C, then the perimeter of the quadrilateral ABCD is

Let A be the centre of the circle x^(2)+y^(2)-2x-4y-20=0 .The tangents at the points B(1,7) and C(4,-2) on the circle meet at the point D .If Delta denotes the area of the quadrilateral ABCD,then (Delta)/(25) is equal to

The length of the tangent to the circle x^(2)+y^(2)-2x-y-7=0 from (-1, -3), is

(i) Find the point at which the circle x^(2)+y^(2)-5x+2y+6=0 , meets the X-axis.

A tangent is drawn to the circle 2(x^(2)+y^(2))-3x+4y=0 and it touches the circle at point A. If the tangent passes through the point P(2, 1),then PA=

The circle x^(2)+y^(2)+4x-7y+12=0 cuts an intercept on y-axis equal to