" I length of convex lens in air is "10cm" .Its focal length in water is (refractive index of glass "=3/2" ,refractive index of water "

(i) If f = + 0.5 m , what is the power of the lens ? (ii) The radii of curvature of the faces of a double convex lens are 9 cm and 15 cm . Its focal length is 12 cm . What is the refractive index of glass ? (iii) A convex lens has 20 cm focal length in air. What is the focal length in water ? (Refractive index of air-water = 1.33 , refractive index of air-glass = 1.5 ).

A lens behaves as a converging lens in air and a diverging lens in water. The refractive index of the material is (refractive index of water =1.33 )

The radius of curvature of convex surface of piano convex lens is 10 cm and its focal length is 30 cm, then the refractive index of the material of the lens is

Focal length of a convex lens of refractive index 1.5 is 2 cm. Focal length of lens when immersed in a liquid of refractive index 1.25 will be

Refractive index of glass with respect to water is (9/8). Refractive index of glass with respect to air is (3/2). Find the refractive index of water with respect to air

Assertion : A concave mirror and convex lens both have the same focal length in air. When they are submerged in water, they will have same focal length. Reason refractive index of water is smaller than be refractive index of air.

Refractive index of glass with respect to water is (9//8) . Refractive index of glass with respect to air is (3//2) . find the refractive index of water with respect to air .