Find the equation of the curve passing through the point `(1,1)` whose differential equation is : `xdy=(2x^2+1)dxdot`

Explanation

Given,

`xdy=(2x^2+1)dxdot`

`dy=((2x^2)/x+1/x)dxdot`

`dy=(2x+1/x)dxdot`

`int dy=int (2x+1/x)dxdot`

`int dy=int (2x)dx+int (1/x)dx`

`y=2(x^2)/2+log|x|+c`

`y=x^2+log|x|+c`

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