Solve the following differential equation : `xcosy\ dy=(x e^xlogx+e^x)dx`

Explanation

`xcosy\ dy=(x e^xlogx+e^x)dx`


`cosy dy=((xe^xlogx)/x+(e^x)/x)dx`

`int cosy dy=int (e^xlogx)dx+int ((e^x)/xdx`

`siny=int (e^xlogx)logxdx+int (e^x)/xdx`


`siny=logx inte^xdx-int [(d(logx))/(dx)e^x]dx+int (e^x)/xdx`


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