If `sum_(r=m)^n ^rC_m=^(n+1)C_(m+1)`, then `sum_(r=m)^n (n-r+1)^rC_m` is equal to `sum_(r=m)^n (n-r+1)^rC_m` is equal to

If sum_(r=m)^(n)hat rC_(m)=^(n+1)C_(m+1), then sum_(r=m)^(n)(n-r+1)^(r)C_(m) is equal to sum_(r=m)^(n)(n-r+1)^(r)C_(m) is equal to

sum_(r=1)^n r (n-r +1) is equal to :

sum_(r=1)^n r (n-r +1) is equal to :

sum_(k=m)^n kC_r

sum_(r=0)^(m)*^(n+r)C_(n) is equal to

sum_(r=0)^m .^(n+r)C_n is equal to