lf `-3` is one of the zeroes of the polynomial `(k-1)x^2+kx+1`, find the value of `k`.

Options

A. `(4)/(3)`
B. `(-4)/(3)`
C. `(2)/(3)`
D. `(-2)/(3)`

Answer

A

Explanation

Given that, one of the zeroes of the quadratic polynomial say `p(x) = (k-1)x^(2)+kx +1` is -3, then `p(-3)=0`
`rArr (k-1)(-3)^(2)+k(-3)+1 =0`
`rArr 9(k-1)-3k +1=0`
`rArr 9k-9 -3k +1=0`
`rArr 6k - 8 =0`
`:. k = 4//3`