If the diagonals of a rhombus are 12cm and 16cm, find the length of each side.

Options

A. 9 cm
B. 10 cm
C. 8 cm
D. 20 cm

Answer

B

Explanation

We know that, the diagonals of a rhombus are perpendicular bisector of each other.
Given, AC=16 cm and BD=12 cm
`therefore` AO=8 cm, BO=6 cm
and `angleAOB=90^(@)`
In right angled `DeltaAOB`

`AB^(2)=AO^(2)+OB^(2)` [by phthagoras theorem]
`rArr AB^(2)=8^(2)+6^(2)=64+36=100`
`therefore` AB=10 cm