If `DeltaABC~DeltaDEF`, AB=4cm, DE=6,EF=9 cm and FD=12 cm, then find the perimeter of `DeltaABC`.

Explanation

Given AB=4 cm,DE=6 cm and EF=9 cm and FD=12 cm
Also, `DeltaABC~DeltaDEF`
`therefore(AB)/(ED)=(BC)/(EF)=(AC)/(DF)`
`rArr 4/6=(BC)/9=(AC)/(12)`
On taking first two terms, we get
`4/6=(BC)/9`
`rArr BC=(4xx9)/6=6 cm`
`=AC=(6xx12)/9=8 cm`
NOw, perimeter of `DeltaABC=AB+BC+AC`
=4+6+8=18 cm