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To divide a line segment AB in the ratio...

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that `/_BAX` is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points is

A

8

B

10

C

11

D

12

Text Solution

Verified by Experts

The correct Answer is:
D
(d) We know that to divide a line segment AB in the ratio m:n, first draw a ray AX which makes an acute angle `angleBAX`, then marked m+n points at equal distance.
Here, m=5,n=7
So, minimum number of these points =m+n=5+7=12
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