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"If" tanA =(1-cosB)/(sinB), "then "tan2A...

`"If" tanA =(1-cosB)/(sinB), "then "tan2A =tanB`

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Given that, `" "tanA =(1-cosB)/(sinB)`
`" "=(1-1+2sin^(2)""(B)/(2))/(2sin""(B)/(2)*cos""(B)/(2))=tan""(B)/(2)`
Now, `" "tan2A=(2tanA)/(1-tan^(2)A)`
`rArr" "tan2A=(2*tan""(B)/(2))/(1-tan^(2)""(B)/(2))` ltBrgt `rArr" "tan2A=tanB`
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