Given x`gt` 0, then value of `f(x)=-3cossqrt(3+x+x^(2))` lie in the interval ….. .

Explanation

To find the interval in which the function \( f(x) = -3 \cos(\sqrt{3 + x + x^2}) \) lies for \( x > 0 \), we can follow these steps:

### Step 1: Determine the range of the cosine function
The cosine function, \( \cos(x) \), has a range of values between -1 and 1 for all real numbers \( x \). Thus, we can express this mathematically as:
\[ -1 \leq \cos(\sqrt{3 + x + x^2}) \leq 1 \]

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