" (a) "(sin3A*cos4A-sin A*cos2A)/(sin4A*sin A+cos6A*cos A)=tan2A

Prove that: (sin3A cos4A-sin Acos2A)/(sin4A sin A+cos6A cos A)=tan2A

Prove that: (sin3Acos4A-sinAcos2A)/(sin4AsinA+cos6AcosA)=tan2A

Prove that: (sin3Acos4A-sinAcos2A)/(sin4AsinA+cos6AcosA)=tan2A

(sin A+sin3A)/(cos A+cos3A)=tan2A

Prove that: (sin5A cos2A-sin6A\ cos A)/(sin A\ sin2A-cos2A cos3A)=t a n A

(cos3A-cos A)/(sin3A-sin A)+(cos2A-cos4A)/(sin4A-sin2A)=(sin A)/(cos2A cos3A)

(cos 4x sin 3x -cos 2x sin x )/(sin 4x sin x+ cos 6x cos x)= tan 2x

Prove that: (sin5A-sin3A)/(cos5A+cos3A)=tanA (sinA+sin3A)/(cosA+cos3A)=tan2A

Prove the following Identities (cos 4x sin 3x - cos 2xsin x)/(sin 4x.sin x +cos 6x.cos x)= tan 2x

Prove that (i) (sec 8A -1)/(sec 4A -1) =(tan 8A)/(tan 2A) (ii) (cos A+ sin A)/(cos A - sin A)-(cos A-sin A)/(cos A+sin A)=2 tan 2A