[-xx+3y(k-3)=0],[12x+ky-3k=0]

For what values of k will the following pair of linear equations have infinitely many solutions? kx+3y-(k-3)=0 12x+ky-k=0

for what values of k will the following pairs of linear equations have infinitely many solutions kx+3y-(k-3)=0 and 12x+ky-k=0

for what values of k will the following pairs of linear equations have infinitely many solutions kx+3y-(k-3)=0 and 12x+ky-k=0

The value of k for which the pair of linear equations kx+3y+(3-k)=0 and 12x+ky-k=0 have infinitely many solution is :

For what values of k will the following pair of linear equations have infinitely many solutions? k x+3y - (k - 3)=0 and 12 x+k y - k=0

{:(kx + 3y = k - 3),(12x + ky = k):}

k x + 3y = k - 3, 12 x + ky = k

Find the value of k for which the pair of linear equations kx + 3y = k-3, 12x + ky = k has no solution.

For which value (s) of k will the pair of equations kx + 3y = k - 3 , 12x + ky = k has no solution ?

For which value (s) of k will the pair of equations kx + 3y = k - 3 , 12x + ky = k has no solution ?