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8.cot[cot^(-1)7+cot^(-1)8+cot^(-1)18]=...

8.cot[cot^(-1)7+cot^(-1)8+cot^(-1)18]=

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If the mapping f(x)=ax+b, a>0 maps [-1,1] on to [0,2] then cot[cot^(-1)(7)+cot^(-1)(8)+cot^(-1)(18)] is equal to

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Prove that : cot^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)3

Prove that : cot ^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)3

Prove that : cot^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)3