Solve the following differential equations: `(dy)/(dx)+y cotx=x^2cotx+2x`

Explanation

`frac{d y}{d x}+y cot x=2 x+x^{2} cot x`


is of the form `frac{d y}{d x}+P y=Q where P=cot x and Q=2 x+x^{2} cot x`
` I. F=e^{int p cdot d x}=e^{int cot x d x}=e^{log sin x}=sin x` since `e^{log x}=x`

Solution is `y times I . F=int Q times I . F {dx}+{c}`
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Rightarrow y sin x=int(2 x sin x+x^{2} cot x sin x) d x`
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