" The e/m ratio is maximum for :- "

The charge/mass (e/m) ratio is maximum for

Two interfering waves have intensities in the ratio 9:1 . Then the ratio of maximum to maximum is intensity is:

Find the ratio of maximum horizontal range and the maximum height attained by the projectile. i.e. for theta_(0) = 45^(@)

Find the ratio of maximum horizontal range and the maximum height attained by the projectile. i.e. for theta_(0) = 45^(@)

The e/m ratio for Anode rays

The e/m ratio for cathode rays: