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If `a_1,a_2,a_3, ......, a_n` are consecutive terms of an increasing A.P.. and `(1^2-a_1) + (2^2 – a_2) + (3^2 – a_3) + ........ + (n^2 - a_n) = ((n - 1)*n*(n+1))/3` then the value of `((a_5+a_3-a_2)/6)` is equal to

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