The temperature at which the speed of sound in air becomes double its value at `0^(@) C` is

Explanation

We know that `(v_(1))/(v_(0)) = sqrt(((T_(1))/(T_0)))`
Here `v_(t) = 2v_(0)`
or `(2v_(0))/(v_(0)) = sqrt(((T_(t))/(273)))`
or `4 = (T_t)/(273)`
or `T_(t) = 4 xx 273 = 1092K`
`t = 1092 - 273 = 819 ^(@)C`