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Find the change in the volume of 1.0 lit...

Find the change in the volume of 1.0 litre kerosene when it is subjected to an extra pressure of `2.0xx 10^5 N m^-2` from the following data. Density of kerosene `= 800 kg m^-3` and speed of sound in kerosene `= 1330 m s^-1`

Text Solution

Verified by Experts

The correct Answer is:
`0.141 cm^(3)`
Sound speed `v = sqrt((B)/(P))`
implies `B = Pv^(2)`
= `800 xx (1330)^(2) = 1.415 xx 10^(9)` N -m
We use `B = |(triangle P)/((triangleV)/V)|`
`DeltaV = (DeltaPV)/(B) = (2 xx 10^(5) xx 10^(-3))/(1.1415 xx 10^(9))`
= ` 1.413 xx 10^(-7)m^(3)`
= `0.141cm^(3)`
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