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If the sound level in a room is increase...

If the sound level in a room is increased from 50 dB to 60 dB, by what factor is the pressure amplitude increased ?

Text Solution

Verified by Experts

The correct Answer is:
`sqrt(10)`
As loudness level increase by 10dB we use
`10 = 10 "log" (I_(2))/(I_(1))`
`(I_(2))/(I_(1)) = 10`
`(DeltaP_(2))/(DeltaP_(1)) = sqrt((I_(2))/(I_(1))) = sqrt(10)`
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