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A sine wave has an amplitude A and wavel...

A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. Then

A

V cannot be equal to v

B

V = v, if A lambda//2pi

C

`V = v, if A = 2pilambda`

D

V =v, lambda = A//pi

Text Solution

Verified by Experts

The correct Answer is:
B
The maximum particle velocity is given by `v = A omega` and the wave velocity is given as `V = omega//k` and the two will be equal when `A = 1//k = lambda//2pi`
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