A block of mass 2m is hanging at the lower and of a ropeof mass m and length the l, the other end being fixed to the ceililng. A pulse of wavelength `lamda_(0)` is produced at the lower of the rope.

The wavelength of the pulse when it reaches the other end of the rope is :

Options

A. `sqrt(3)lambda_(0)`
B. `sqrt((3)/(2))lambda_(0)`
C. `lambda_(0)`
D. `(lambda_(0))/(2)`

Answer

B

Explanation

We use `v_(1) = sqrt((T_(1))/(mu)) = sqrt((2mg)/(mu)) = vlambda_(0)`
`v_(2) = sqrt((3mg)/(mu)) = vlambda_(2)`
Comparing, we get
`lambda_(2) = sqrt((3)/(2))lambda_(0)`