two particle of medium disturbed by the wave propagation are at `x_(1)=0 and x_(2)=1 cm`. The respective displacement (in cm) of the particles can be given by the equation:
`y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8)` the wave velocity is

Options

A. 16 cm/sec
B. 24 cm/sec
C. 12 cm/sec
D. 8 cm/sec

Answer

B

Explanation

We use `omega = 3pi`
`f = (omega)/(2pi) = 1.5`
`Deltax = 1.0 cm`
`phi = (2pi)/(lambda) Deltax`
`(pi)/(8) = (2pi)/(lambda) xx 1`
`lambda = 16 cm`
`v = flambda = 16 xx 1.5` = 24cm/sec.