The equation of a wave is
`y=4 sin[(pi)/(2)(2t+(1)/(8)x)]`
where y and x are in centimeres and t is in seconds.

Options

A. The amplitude, wavelength, velocityand frequency of wave are `4 cm, 16cm,32cm^(-1)` and 1 Hz respectively with wave propagating along + x direction
B. The amplitude, wavelength, velocityand frequency ofwave are `4 cm,32 cm, 16cm^(-1)` and 0.5 Hz respectively with wave propagating along -x direction
C. Two positions occupied by the particle at time interval of 0.4 s have a phase difference of 0.4 `pi` radian
D. Two positions occupied by the particle at separation of 12 cmhaveaphasedifferenceof `135^(@)`

Answer

B, C, D

Explanation

Comparing the equation with the general equation of the wave `Y = A sin(2pi)(t//T - x//lambda)]` we get option (B) is correct and as wave length is 4cm we can calculate the phase difference between two positions of the medium particle by using the relation `(2pi//lambda)Delta` A which gives option(C) and (D) are correc