AB is a diameter of a circle. `AH and BK` are perpendiculars from A and B respectively to the tangent at P Prove that `AH + BK = AB`.

AB is a diameter of circle. P is a point on the semicircle APB. AH and BK are perpendiculars from A and B respectively to the tangents at P. Prove that AH+BK=AB .

AB is a diameter of a circle.P is a point on the semi-circle APBAHandBK are perpendiculars from Aand B respectively to the tangent at P. Prove that AH+BK=AB

O is the centre of a centre having diameter AB. P is any point on the circle. Draw a perpendicular from P to AB, which meets AB at N. Prove that PB^2 =AB.BN

AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB . The tangent at B meets the line AC produced at E then AE is equal to -

AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB. The tangent at B meets the line AC produced at E then AE is equal to -

AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB. The tangent at B meets the line AC produced at E then AE is equal to

AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB . The tangent at B meets the line AC produced at E then AE is equal to -

AB is a diameter of a circle. CD is a chord parallel to AB and 2CD = AB . The tangent at B meets the line AC produced at E then AE is equal to -

AB is a diameter of circle. P is point on circle and a perpendicular line is drawn on AB at N from it. If radius is 7 cm. and PB = 12 cm. then BN is (in cm)-