[" The frictional force of the air on a body of mass "],[0.25kg" ,falling with an accleration of "9.2m/s^(2)" ,"],[" will be: "]

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

Find the friction force due to air on a body of mass 1 kg falling with acceleration 8 m//s^(2) :-

A body of mass 1.0 kg is falling with an acceleration of 10 m//s^(2) . Its apparent weight will be (g=10m//sec^(2))

A force of 100N acts on a body of mass 0.25kg for 2s . Calculate acceleration of the body and its change in momentum.

State the magnitude and direction of the force of gravity acting on a body of mass 5 kg. Take g = 9.8 m s^(-2)