`(1-2sin^2alpha)/(1+sin2alpha)=(1-tanalpha)/(1+tanalpha)`

(1-2sin^(2)alpha)/(1+sin2 alpha)=(1-tan alpha)/(1+tan alpha)

tan2alpha-tanalpha(1+sec2alpha)=

If tanbeta=(n^2sinalpha cdot cosalpha)/(1-n^2sin^2alpha) then show that tan(alpha-beta)/(tanalpha)=1-n^2

If tanbeta=(nsinalphacosalpha)/(1-nsin^2alpha) ,show that tan(alpha-beta)=(1-n)tanalpha

If -pi/2 lt alpha lt pi/2 , then prove that tan^(-1)((3sin2alpha)/(5+3cos2alpha))+tan^(-1)((tanalpha)/4)=

The ratio between (1+cos alpha)/(sin^(2)alpha) and 1+((1+cos alpha)/(sin alpha))^(2) in that order is

If tanalpha=3, calculate : (2 sin 2alpha-3sin2alpha)/(4 sin2alpha+5cos2alpha) .

if tanbeta=(nsinalphacosbeta)/(1-nsin^2alpha) then prove that tan(alpha-beta)=(1-n)tanalpha.

Simplify [(3sin2alpha)/(5+3cos2alpha)]+tan^(-1)[(tanalpha)/4],w h e r e-pi/2