[" socaight vertical conductor carrier a curront."],[" reapoines om due north of is the maguete "],[" metwoton is found to be "20 mu" ? due cast.The "],[" megnetic induction at a point lo con eqectit "],[" will be "]

A straight vertical conductor carries a current. At a point 5cm due north of it, the magnetic induction is founded to be 20muT due east. The magnetic induction at a point 10cm east of its will be

A vertical wire carriers a current upwards. The magnetic field at a point due north of the wire is directed

Due to a straight vertical current carrying conductor, a null point occurred at P on east of the conductor. The net magnetic induction at a point 'Q' which is at same distance on north of the conductor is

A long vertical wire carriers a current of 10 amperes flowing upwards through it at place where the horizontal component of the earth's magnetic induction is 0.3 gauss. Then the total magnetic induction at a point 5 cm from the wire due magnetic north of the wire is

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. If the current density in a linear conductor of radius a varies with r according to relation J=kr^2 , where k is a constant and r is the distance of a point from the axis of conductor, find the magnetic field induction at a point distance r from the axis when rlta. Assume relative permeability of the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. If the current density in a linear conductor of radius a varies with r according to relation J=kr^2 , where k is a constant and r is the distance of a point from the axis of conductor, find the magnetic field induction at a point distance r from the axis when rlta. Assume relative permeability of the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. In the above question, find the magnetic field induction at a point distance r from the axis when rgta. Assume relative permeability of the medium surrounding the conductor to be unity.