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Find the point on the curve y^2=4x which...

Find the point on the curve `y^2=4x` which is nearest to the point (2, 1).

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Distance between `P(x, y)` and `(2,1)` is

`{S}^{2}=({x}-2)^{2}+({y}-1)^{2}`

`{S}^{2}=(frac{{y}^{2}}{4}-2)^{2}+({y}-1)^{2}`

`2 S frac{d S}{d x}=frac{y^{3}}{4}-2`

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