[" If "y=arccot(x^(2)+1),0

Range of function f(x)=arccot(2x-x^(2)) is [(pi)/(4),(3 pi)/(3)](b)[0,(pi)/(4)][0,(pi)/(2)] (d) [(pi)/(4),pi]

If 2xydy=(x^(2)+y^(2)+1)*dx,y(1)=0 and y(x_(0))=sqrt(3) then x_(0) can be

STATEMENT-1: If three points (x_(1),y_(1)),(x_(2),y_(2)),(x_(3),y_(3)) are collinear, then |{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=0 STATEMENT-2: If |{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=0 then the points (x_(1),y_(1)),(x_(2),y_(2)),(x_(3),y_(3)) will be collinear. STATEMENT-3: If lines a_(1)x+b_(1)y+c_(1)=0,a_(2)=0and a_(3)x+b_(3)y+c_(3)=0 are concurrent then |{:(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3)):}|=0

Solve each of the following initial value problems: (dy)/(dx)+(2x)/(x^(2)+1)y=(1)/((x^(2)+1)^(2)),y(0)=0( ii) (x^(2)+1)y'-2xy=(x^(4)+2x^(2)+1)cos x,y(0)=0

The area of the region bounded by curves y=1-x^(2), x+y+1=0 and x-y-1=0 is

If x_(1),x_(2),y_(1),y_(2)in R if ^(@)0

If the area of the region {(x,y):0<=y<=x^(2)+1,0<=y<=x+1,0<=x<=2} is A, then the value of 3A-17 is

Find the area of the region {(x,y):0<=y<=x^(2)+1,0<=y<=x+1,0<=x<=2}