A container having a liquid of density `rho` is moving downwards with acceleration `g/2`. Find the pressure difference between two vertical points in the liquid separated by `h`

A beaker containing a liquid of density rho moves up with an acceleration a . The pressure due to the liquid at a depth h below the free surface of the liquid is.

A sealed tank containing a liquid of density rho moves with a horizontal acceleration a, as shown in the figure. The difference in pressure between the points A and B is

A sealed tank containing a liquid of density rho moves with horizontal acceleration a as shown in the figure. The difference in pressure between two points A and B will be

A closed rectangular vessel completely filled with a liquid of density rho moves with an acceleration a =g. The value of the pressrure difference at point A and B i.e., (P_1 -P_2) is :

If the boiling point difference between the two liquids is not musch then they can be separated by:

A vertical communicating tube contains a liquid of density rho . If it moves with a horizontal acceleration a , pressure at A is equal to :

If a vessel containing a fluid of density rho upto height h is accelerated vertically downwards with accelerations a_(0) . Then the pressure by fluid at the bottom of a vessel is

A U-tube of base length l filled with same volume of two liquids of densities rho " and " 2rho is moving with an acceleration a on the horizontal plane. If the height difference between the two surfaces (open to atmosphere) becomes zero, then height h is given by

A U -tube of base length l filled with the same volume of two liquids of densities rho and 2rho is moving with an acceleration 'a' on the horizontal plane. If the height difference between the two surfaces (open to atmosphere) becomes zero, then the height h is given by