The shortest distance between the line `(x-1)/(2)=(y+1)/(3)=(z)/(1)` and the line `(x+1)/(1)=(y+4)/(1)=(z+1)/(1)` is

Equation of the line of the shortest distance between the lines (x)/(1)=(y)/(-1)=(z)/(1) and (x-1)/(0)=(y+1)/(-2)=(z)/(1) is:

Equation of the line of the shortest distance between the lines (x)/(2)=(y)/(-3)=(z)/(1) and (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) is

Find the magnitude of the shortest distance between the lines (x)/(2)=(y)/(-3)=(z)/(1) and (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) .

The shortest distance between the lines (x-3)/(2) = (y +15)/(-7) = (z-9)/(5) and (x+1)/(2) = (y-1)/(1) = (z-9)/(-3) is :

Statement 1: The shortest distance between the lines (x)/(-3)=(y-1)/(1)=(z+1)/(-1) and (x-2)/(1)=(y-3)/(2)=((z+(13/7))/(-1)) is zero.Statement 2: The given lines are perpendicular.

Find the shortest distance between the lines (x+3)/(-4) =(y-6)/(3)=(z)/(2) " and " (x+2)/(-4) =(y)/(1)=(z-7)/(1)

The shortest distance between the lines (x-2)/(2)=(y-3)/(2)=(z-0)/(1) and (x+4)/(-1)=(y-7)/(8)=(z-5)/(4) lies in the interval

The shortest distance between the lines (x)/(m_(1))=(y)/(1)=(z-a)/(0) and (x)/(m_(2))=(y)/(1)=(z+a)/(0)