[" A capacitor of capacitance "1 mu F" has "],[" initial charge "10 mu C" .Now it is connected "],[" to a source of voltage "20" volt.The charge "],[" in steady state on the capacitor is : "]

The circuit is in a steady state. The charge in capacitor C_1 is

The charge in the 2 mu F capacitor at steady state is

A capacitor of capacitance C carrying charge Q is connected to a source of emf E . Finally, the charge on capacitor would be

In the circuit shown , charge on the 5 mu F capacitor is :

A parallel plate capacitor of capacitance 1 mu F has a charge of + 2 mu C on one of the plates and a charge of + 4 mu C on the other. The potential difference developed across the capacitor is

A capacitor of capacitance 6 mu F is charged upto 100 volt. The energy stored in the capacitor is

The plates of capacitor of capacitance 10 mu F , charged to 60 mu C , are joined together by a wire of resistance 10 Omega at t = 0, then (i) the charge on the capacitor in the circuit at t=0 is :

A battery of 20V is connected to a capacitor of capacitance 10 muF . Now battery is removed and this capacitor is connected to a second uncharged capacitor. If the charge distributes equally on these two capacitors, the total energy stored in the two capacitors will be

The plates of capacitor of capacitance 10 mu F , charged to 60 mu C , are joined together by a wire of resistance 10 Omega at t = 0, then ltbr gt (ii) the charge on the capacitor in the circuit at t = 100 mu s is :

A capacitor of 8 F is connected as shown in the figure. At steady state Charge on the plates of the capacitor