The least value of the function `f(x)=x^3-18 x^2+96 x` in the interval `[0,9]` is 126 (b) 135 (c) 160 (d) 0

Explanation

To find the least value of the function \( f(x) = x^3 - 18x^2 + 96x \) in the interval \([0, 9]\), we will follow these steps:

### Step 1: Find the derivative of the function
We start by differentiating the function \( f(x) \):
\[ f'(x) = \frac{d}{dx}(x^3 - 18x^2 + 96x) = 3x^2 - 36x + 96 \]

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